Two dice is rolled. What is the probability that it didn't have a same number
(2,3) , (1,2) is allowed, (6,6) isn't
(1,2) , (2,1) is different
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6^n= total no. of outcomes, where n is no. of dices here, 6^2=36. therefore, there are total 36 outcomes. there are only 6 same nos.[ (1,1),(2,2),(3,3),(4,4),(5,5),(6,6)] so we subtract 6 from 36 and thus the event possible outcomes become 30. P(e)= 30/36=5/6