If a + a 1 = 2 cos 6 ∘ , find a 1 0 0 0 + a 1 0 0 0 1 + 1 .
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
It really a nice question.
I want a redo lol. I had the same exact solution, but I forgot to add the 1.
I did De Moivre's Theorem
very nice solution!
What about e^-6i?
Log in to reply
If a = e − 6 i , then a 1 0 0 0 + a 1 0 0 0 1 + 1 = e − 6 0 0 0 i + e 6 0 0 0 i + 1 which is the same expression.
Did the same way exactly.It was a cute and a nice question.
Problem Loading...
Note Loading...
Set Loading...
a + a 1 = 2 cos 6 ∘ ⇒ a 2 − 2 cos 6 ∘ a + 1 = 0 ⇒ a = 2 2 cos 6 ∘ ± 4 cos 2 6 ∘ − 4 = cos 6 ∘ ± i sin 6 ∘ = e ± 6 ∘ i
⇒ a 1 0 0 0 + a 1 0 0 0 1 + 1 = e 6 0 0 0 ∘ i + e − 6 0 0 0 ∘ i + 1 = 2 cos 6 0 0 0 ∘ + 1 = 2 cos 2 4 0 ∘ + 1 = 2 ( − 2 1 ) + 1 = − 1 + 1 = 0