Difference

Geometry Level 3

The diagram above shows a circle inscribed inside a square of side length 10 10 , which has a right triangle of legs length x x and 2 x 2x , and hypotenuse length y y inscribed in it.

The difference between the area of the orange \color{#ee7600}{\text{orange}} shaded region and the blue \color{#3D99F6}{\text{blue}} shaded region can be written as a ( b a π ) a(b-a\pi ) for integers a a and b b . Let the digit sum of b b be B B . Then find the remainder of B a a ÷ B \large\overline { Baa } \div B


The answer is 6.

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1 solution

Personal Data
May 8, 2015

Since the triangle is inscribed in the circle then it's hypotenuse is also the diameter of the cricle so y = 10 y=10 .

From the pythagorean theorem we can calculate that y = x 5 y=x\sqrt { 5 } so x = 2 5 x=2\sqrt { 5 } .

The area of the blue shaded area is x 2 = 20 { x }^{ 2 }=20 and the area of the orange shaded area is 10 2 π 5 2 = 100 25 π { 10 }^{ 2 }-\pi { 5 }^{ 2 }=100-25\pi .

The difference between them is 80 25 π = 5 ( 16 5 π ) 80-25\pi =5\left( 16-5\pi \right) . Therefore a = 5 a=5 and b = 16 b=16 and the digit sum of b b is 7 7 ,

Finally B a a = 755 \overline { Baa } =755 so the remainder is equal to 6 6 .

Smartly done :)

Mahtab Hossain - 6 years, 1 month ago

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