Differences in Medians

Geometry Level 2

Consider line segment A B \overline{AB} . Let C C be the midpoint of line segment A B \overline{AB} . Points D D and E E exist such that A B D \triangle ABD and A B E \triangle ABE are right triangles with right angles at points D D and E E , respectively. Find C D C E \overline{CD}-\overline{CE} .

0 0 1 1 Cannot be determined 2 \sqrt{2}

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1 solution

John Mead
Jun 18, 2014

As A B D \bigtriangleup ABD is a right triangle, it can be inscribed in a semicircle with its hypotenuse A B \overline{AB} as its diameter and D D on the circumference of the corresponding circumscribing circle. Likewise for A B E \bigtriangleup ABE , which shares a hypotenuse, and hence a circumscribing circle, with point E E on its circumference. Point C C is therefore the center of the corresponding circle and points D D and E E are on the circle, thus C D \overline{CD} and C E \overline{CE} are both radii of the circle with center C C . Therefore these segments are congruent, giving C D C E = 0 \overline{CD} - \overline{CE} = \boxed{0} .

i don't understand any of the numbers

orobosa orumwense - 11 months, 3 weeks ago

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