Different between the angles in a parallelogram

Geometry Level 3

Let the two sides and the diagonal of a parallelogram be denoted by a − 2 , a − 4 a-2,a-4 and a a , respectively, where a a is a positive integer.

If the smallest absolute difference of angles between 2 non-opposite interior angles of this parallelogram can be expressed as b 15 3 b \sqrt[3]{15} degrees, where b b is an integer, what is b b ?


The answer is 0.

Omar Sayeed Saimum by Omar Sayeed Saimum , 21, Bangladesh

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1 solution

The smallest difference will be 0 if it is a rectangle. We see that it is possible because 10² = 8² + 6²

which fulfill our requirement. So, 0*(15^{⅓})=0 b=0

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