Different coats
There were three people: A , B , C , D , E , F , G and H , and all of them were wearing coats. They entered a conference together and put their coats on 8 similar pegs.When they were leaving, the lights went out and they held a coat each in the darkness. What is the probability that none of them are holding their own coat?
Give your answer in decimals.
If you have a formula for these types of questions, please share it with the community in the Discussions.
The answer is 0.3678.
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1 solution
To solve similar questions in which the number of people and number of hats(objects) is the same, then use this equation:
{n-1[(n-1)! ÷ 2]} ÷ (n!) Simply substitute 8 into this equation: {8-1[(8-1)! ÷ 2]} ÷ 8! = 17,640 ÷ 40,320 = 0.4375