Digit problem 1 by Dhaval Furia
In a six -digit number, the sixth , that is, the rightmost, digit is the sum of the first three digits, the fifth digit is the sum of first two digits, the third digit is equal to the first digit, the second digit is twice the first digit and the fourth digit is the sum of fifth and sixth digits. Then, the largest possible value of the fourth digit is _____
The answer is 7.
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1 solution
Let the number be A B C D E . Then
F = A + B + C , E = A + B , C = A , B = 2 A , D = E + F = A + B + A + B + C = 2 A + 2 B + C = 2 A + 4 A + A = 7 A .
Since D is a single digit number, therefore D = 7 .
The number is 1 2 1 7 3 4 .