Digit Sum

${ 2 }^{ 2012 }+{ 2 }^{ 2014 }$ can be factored as ${ 2 }^{ 2012 }(1+ { 2 }^{ 2 })$ which equals to ${ 2 }^{ 2012 }\cdot 5$ .

Factor again would give us: ${ 2 }^{ 2012 }\cdot 5={ 2 }^{ 2011 }\cdot 2\cdot 5={ 2 }^{ 2011 }\cdot 10$

We already know the digit sum of ${ 2 }^{ 2011 }$ . If that digit sum is multiplied by $10$ , it would be the same digits with an extra $0$ in the one's place. So the digit sum would be $2738+0=\boxed {2738}$