Diophantine Equations (Problem 4)

Number Theory Level pending

x + x 3 = 5 y 2 x + x^3 = 5y^2

Find the solution where x , y x,y are integers


The answer is 0.

A Former Brilliant Member by A Former Brilliant Member

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1 solution

If x > 1 , y ≠ x x > 1, y \neq x

Therefore the solution is x = 0 , y = 0 x = 0, y = 0 .

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Yajat, actually meaning of solution is values of x here. Solution doens't means just putting all values equal, as you've done in all questions. Otherwise good question.

Aryan Sanghi - 1 year ago

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