x → ∞ lim lo g 1 0 ( x 2 ) ln ( x + ln ( x + ln ( x x 1 ) ) )
This expression can be expressed as B A ( ln ( C ) + ln ( D ) ) for co-prime positive integers A and B , and prime numbers C and D .
Find A + B + C + D
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Answer can't be 14 because D can't be 1. It is given that C and D are prime numbers, and 1 is not a prime.
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thanks i just forget that point actually i forget to read it
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In denominator change base and simply using property of log i.e,log(x square ) as 2log(x) further i was not getting any idea so i applied evergreen method L'Hospital simplified further i saw some coming in 1/x type form and applying limits to them =o then i remain with
numerator=1/( x + ln(x+1/x(lnx) )
denominator = 2/x
multiplying both of above by x gives us half ans 1/2 and as we have changed limits we have separately log10 to base e in multiplication
and answer comes to =1/2 ( log10) now 10 can be written as 2x5 or 1x10
getting values of A=1 B=2 C=2 D=5 summing up results A+B+C+D= 10 that is final answer ............ (answer can't be 14 as D=1 is not possible given D is a prime number :) :) )