Discounts

$100 \times 0.8 = 80 \\ 80 \times 0.9 = 72$

Therefore the item is now at $72 \%$ of its original price i.e $(100-72) \%=\large \color{#20A900}{\boxed{28 \%}}$ discount.

100 * 20/100 = 20
100 - 20 = 80 * 10/100 = 8
there fore total discount = 20 + 8 = 28%

the price of the item was $100. 20% of 100 would be 100-20 which is 80. Then, taking a further 10% off of 80 would be 80-8 which is 72. 100-72 is 28%.

(1 - 0.8x0.9) x 100% = 28%

A = Artículo (A - 20%A) - 10% (A - 20%A) = A - 20%A - 10%A + 200/10000A = A - (20% + 10% - 2%)A = A - 28%A Entonces el descuento final fué 28%

After first discount of 20% the value of the product has become 80 %.Discount of 10 % on this rediced value is 8%.Hence total discount is 20+8=28%

We can assum that An Item as 100%,

1st Discount 20% --> 80%

2nd Discount 10% --> 90%, so solution as below:

= 100% - 80% * 90%

= 100% - 72%

=28%

Discount 1 : 100 x 80% = 80 Discount 2 : 80 x 90% = 72 Total Discount : 100-72=28

(1-20%) x (1-10%) = 1 - 72% so the discount is 28%