Disguise its all that matters !!!!!!

Calculus Level pending

Calculate the absolute value of the limit given below. Ξ = lim h 0 sin h + sin 2 h + sin 3 h + sin 3 π cos h + cos 2 h + cos 3 h + cos 3 π 2 \Xi=\lim_{h \to 0} \dfrac{\sin h + \sin 2h+ \sin 3h \cdots + \sin 3\pi}{\cos h +\cos 2h +\cos 3h \cdots + \cos \dfrac{3\pi}{2}} .

Hint: Take a look at this .


The answer is 2.

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