Displacement vs. Distance

Distance ( $d$ ) $= 80 + 150 = 230$ cm

By Pythagoras theorem we can find the displacement:

$s = \sqrt{80^{2}+150^{2}}$

$s = \sqrt{6400+22500}$

$s = \sqrt{28900}$

$s = 170$ cm

So, the answer is: $d - s = 230 - 170 = \boxed{60 cm}$

The Distance travelled by Ron the Mouse is $80+150 = 230$ Centimeters. By the Pythagorean Theorem we get that the magnitude of Displacement of Ron the Mouse is 170 Centimeters. therefore the difference of the 2 is $230-170 = \boxed{60}$

Displacement is diagonal it is 170 so difference is 150+ 80 – 170 = 60 cm

The distance traveled=d=80+150=230cm

The magnitude of displacement=sq.rt.((150)^2+(80)^2) = 170cm

Therfore, d-s=60

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s = 50 + 80 = 230 d = (50² + 80²)^1/2

s - d = - 60 d - s = 60

there is a error in the problem

distance taken = 230 displacement= 150

d-s= 60

80+150=230 cm = d 170cm= s so d-s = 230-170= 60 cm

total distance traveled (d) = 80 +150 = 230 cm,
displacement (s) = (80^2+150^2)^(1/2) = 170 cm,
d-s = 230 -170 = 60 cm

150+80-(sqrt(150^2+80^2))

sq rt [ (80)^2 + (150)^2 ] - (170)= 60 cm