Dissipated Energy

For the shown circuit, Each capacitor has a capacitance 1pF. The right side capacitor has an initial voltage 2V, while the left side capacitor has an initial voltage 0V. Does the energy dissipated in the resistor, due to the current passing through it from t=0 to t ==> infinity, depend on R value?

Yes, and also depends on other circuit's parameters No It only depends on initial voltages' levels Yes, and doesn't depend on other circuit's parameters

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1 solution

Ahmed Kassem
May 20, 2019

The initial charge stored on the right capacitor will be distributed equally between the two capacitors.

The energy loss in the resistance= Energy stored initially in the right cap - energy stored finally in the two capacitors

This subtraction value only depends on initial voltages and capacitances values. It has nothing to do with the resistance value!

You can reach to the same result by integrating power dissipated by the resistance over time from 0 to infinity.

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