Distance, Rate, and Time

Algebra Level 2

Phillip started running away in a straight line from a point at a constant speed. 30 minutes after he started running, he was 2 miles away from his starting point. At what speed (in mph) was Phillip running?

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Ian Watson-Hemphill by Ian Watson-Hemphill , 20, USA

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2 solutions

Given: distance = 2 miles

time = 30 minutes = 0.5 hours

Formula: s p e e d = d i s t a n c e t i m e speed = \dfrac{distance}{time}

Substitute:

s p e e d = 2 0.5 = 4 m p h speed = \dfrac{2}{0.5}=\boxed{4mph}

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Distance = Rate*Time. The distance is 2 miles, and the time is 30 minutes. Therefore, the rate is equal to d i s t a n c e t i m e \frac{distance}{time} , or 2 m i 1 / 2 h r s \frac{2 mi}{1/2 hrs} , which we simplify to 4 m p h . \boxed{4 mph.}

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