A train starts it's journey from still and travels a distance of
within
and comes back to still . Within the journey it obtains a maximum velocity of
. If it's value of acceleration and deceleration is equal, find the distance that the train traveled in it's maximum speed in
meters
?
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Answer
= 25 * [2 * (2.5 *1000 / 25) - 3 * 60].
= 25 * [200 - 180].
= 500 m