Divide 3

111 is divisible by 3.

222 is divisible by 3.

333 is divisible by 3.

444 is divisible by 3.

555 is divisible by 3.

Let M M be a positive integer with all the same digits but none of its digits are 3.

True or false:

If M M has N N digits, where N N is divisible by 3, then M M must be divisible by 3.

False True

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1 solution

M M is divisible by 3 3 if the sum of its digits is a multiple of 3 3 .

As per question, let it have 3 k 3k digits.

So, the sum of the digits of M = 3 k × N = 3 ( N k ) , M=\space 3k\space \times\space N=3(Nk), which is obviously divisible by 3. 3.

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