Divide Sum of Divisors

Level pending

Let A A be the sum of all divisors of 2 18 + 1 2^{18}+1 .

What is the value of [ A 1000 ] [\frac{A}{1000}] ?

( [ x ] [x] is the greatest integer function )


The answer is 351.

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1 solution

Joe Mansley
Apr 16, 2021

2 18 + 1 = ( 2 6 + 1 ) ( 2 12 2 6 + 1 ) = 65 × 4033 2^{18}+1 = (2^6+1)(2^{12}-2^6+1) = 65 \times 4033

4033 = 37 × 109 4033 = 37 \times 109 (I don't know a fast way to find these factors. I just checked divisibility by 3,5,7,...)

So 2 18 + 1 = 5 × 13 × 37 × 109 2^{18}+1=5 \times 13\times 37\times 109

So A = ( 1 + 5 ) ( 1 + 13 ) ( 1 + 37 ) ( 1 + 109 ) = 351120 A=(1+5)(1+13)(1+37)(1+109) = 351120

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