Fractional part of 7

Number Theory Level 1

Is the number 93128571 divisible by 3?

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Fred Fan by fred fan , 21, Canada

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5 solutions

Jay Robinson
Apr 21, 2015

First remove all digits which are multiples of 3, before adding the remaining digits, and if that is divisible by three then the original number is necessarily divisible by three. "93128571", "128571", "1+2+8+5+7+1", "24", which is divisible by three, so the initial number was.

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Gagan Jain
Apr 21, 2015

If the sum of the digits of a number is a multiple of 3, then the number is divisible by 3. This is the divisibilty test for 3. In this case, 9+3+1+2+8+5+7+1 = 36 and 3+6 = 9, which is a multiple of 3. So this is divisible by 3

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Krishna Shankar
Apr 20, 2015

By adding the digits 9. that is the divisibility test for 3. hence its divisible by 3

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Ojaswini Bahuguna
May 13, 2015

test of divisibility just add all the digits - 9+3+1+2+8+5+7+1=36 36 is divisible by 3 .therefore,93128571 is divisible by 3.

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Since nos. that are divisible by 9 are also divisible by 3, 9+3+1+2+8+5+7+1 = 36/9= 4 So, it is divisible.

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