F i n d t h e s m a l l e s t n o w h i c h w h e n d i v i d e d b y 3 5 l e a v e s a r e m a i n d e r 2 5 , w i t h 4 5 l e a v e s 3 5 a s a r e m a n d w i t h 5 5 l e a v e s 4 5 .
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L e t t h a t n u m b e r b e x . T h e n x = 2 5 m o d 3 5 x = 3 5 m o d 4 5 x = 4 5 m o d 5 5 S o , i t c a n b e r e w r i t t e n a s x = − 1 0 m o d 3 5 x = − 1 0 m o d 4 5 x = − 1 0 m o d 5 5 H e n c e t h e a n s w e r i s 3 4 5 5 i e . 1 0 l e s s t h a n 3 4 6 5 ( L C M o f 3 5 , 4 5 , 5 5 )
Can you explain how you got -10
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25 mod 35 can be re written as 25-35 mod 35 which is -10 mod 35 this is a property of mod function. also when we divide something with 35 and we get 25 as remainder we can increase the quotient by 1 and subtract 35 from 25.
rajdeep bhaiya mod function padhne ke liye kaun si book se padhe koi specific book hai ya fir kisi website se padhe .
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No ÷ 35 remainder 25
No ÷ 45 remainder 35
No ÷ 55 remainder 45
here the difference in divisor and remainder (35 – 25), (45 – 35) and (55 – 45) = 10 constant
so least number = LCM of divisors – difference
required least number = (LCM of 35, 45, 55) – 10
= 3455