Divisible by 11...

Find the largest number divisible by 11, that is made up of any nine of the ten digits from 0 through 9, each digit appearing exactly once.


The answer is 987652413.

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1 solution

Chew-Seong Cheong
Oct 20, 2014

The divisibility rule of 11 is that the difference between the sums of alternative digits are divisible by 11. To solve the problem we have to arrange the digits to follow the rule and at the same time give the largest number. Obvious the highest digit should be 9 and then follow by the largest remaining numbers whenever possible.

The largest number has the following sums of alternative digits.

9 + 7 + 5 + 4 + 3 = 28 ( 8 + 6 + 2 + 1 ) = 17 D i f f e r e n c e = 11 \begin{matrix} 9+7+5+4+3= & 28 \\ -(8+6+2+1)= & -17 \\ Difference= & 11 \end{matrix}

The largest number is 987652413 \boxed {987652413} .

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