Divisible by 14?

How many of the following octal (base 8) numbers are divisible by 1 4 10 14_{10} (decimal)?

  • A. 3460343610753625236502356420335435350113534544 2 8 34603436107536252365023564203354353501135345442_8

  • B. 23425340745602342546074520134363252556770435235064 5 8 234253407456023425460745201343632525567704352350645_8

  • C. 235767342350235634523405234025305235005345200053500 0 8 2357673423502356345234052340253052350053452000535000_8

  • D. 23043046702050475001003363607070502035345643054650345 6 8 230430467020504750010033636070705020353456430546503456_8

  • E. 3574560456354235046546657043554350657345045506 7 8 35745604563542350465466570435543506573450455067_8

  • F. 4702345034620345325047665057506405775064034606757 0 8 47023450346203453250476650575064057750640346067570_8

  • G. 547045254604670675606355346040532010142340152305215 4 8 5470452546046706756063553460405320101423401523052154_8

  • H. 326043503645754643243464604754054253466450324560 4 8 3260435036457546432434646047540542534664503245604_8

  • I. 14670545707070456770064567045064560421023412351503 2 8 146705457070704567700645670450645604210234123515032_8

6 1 5 4 8 7 2 3

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1 solution

I'll leave the proof to others, but here is the trick to solve this problem. 14 = 2 * 7, so the number is divisible by 14 if it is divisible by 2 and by 7.

i. 2 divides 8, so an octal number is divisible by 2 if the last digit is even (like with base 10).

ii. In base 10, a number is divisible by 9 if the sum of the digits of the number is divisible by 9; likewise, in base 8, a number is divisible by 7 if the sum of the digits is divisible by 7. If you sum octally, you can keep adding the digits, and if the result is 0 or 7, the number is divisible by 7, otherwise not. E.g. the sum of E is 196 (decimal), that is 304 (octal), and 3 + 4 = 7.

The (decimal) digitsums are resp.: 159, 185, 155, 166, 196, 189, 172, 187 and 178. 196 and 189 are divisible by 7, but E is an odd number; only F is divisible by 2 and 7, and therefore by 14.

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