Define to be the number of positive divisors of for a positive integer For example,
What is the smallest positive integer such that no satisfies the equation
If you think there is no answer, write 0 as your answer.
Bonus: Solve this without a computer program.
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The answer is k = 1 8 .
First let's show that every smaller number equals d ( n ) n for some n . This can be done by inspection:
Now there is a relatively trivial upper bound on d ( n ) , namely d ( n ) ≤ 2 n . This is clear because divisors can be put into pairs which multiply to n , so that one of the numbers in each pair is ≤ n . (This still works for perfect square n ; think about it if you're unsure.)
So this gives d ( n ) n ≥ 2 n n = 2 n . So we need only compute d ( n ) n up to n = 1 2 9 6 to be sure that d ( n ) n = 1 8 has no solution. This is easy for a computer.