Divisor Equation(2)

Define d ( n ) d(n) to be the number of positive divisors of n n for a positive integer n . n. For example, d ( 2018 ) = 4. d(2018)=4.

What is the smallest positive integer k k such that no n n satisfies the equation n d ( n ) = k ? \frac{n}{d(n)}=k?

If you think there is no answer, write 0 as your answer.


Bonus: Solve this without a computer program.


The answer is 18.

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1 solution

Patrick Corn
Jul 25, 2018

The answer is k = 18. k=18.

First let's show that every smaller number equals n d ( n ) \frac{n}{d(n)} for some n . n. This can be done by inspection:

k n
1 1
2 8
3 24
4 36
5 40
6 72
7 56
8 80
9 108
10 180
11 88
12 240
13 104
14 252
15 360
16 128
17 136

Now there is a relatively trivial upper bound on d ( n ) , d(n), namely d ( n ) 2 n . d(n) \le 2\sqrt{n}. This is clear because divisors can be put into pairs which multiply to n , n, so that one of the numbers in each pair is n . \le \sqrt{n}. (This still works for perfect square n n ; think about it if you're unsure.)

So this gives n d ( n ) n 2 n = n 2 . \frac{n}{d(n)} \ge \frac{n}{2\sqrt{n}} = \frac{\sqrt{n}}2. So we need only compute n d ( n ) \frac{n}{d(n)} up to n = 1296 n=1296 to be sure that n d ( n ) = 18 \frac{n}{d(n)}=18 has no solution. This is easy for a computer.

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