Do Algebra and electricity mix ???
Electricity and Magnetism
Level
3
A resistant (nCr) ohms is connected in parallel with another one of the same value in a circuit, if a battery with emf ( n^2 ) with an internal resistant (n/4) is connected to the circuit , and the current that flows is (4) A , find the value of (r)
n-2
2
n-2 , 2
n
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1 solution
Given,
2 resistances of nCr are in parallel. so, R=nCr/2.
r=internal resistance=n/4.
E=emf=n^2.
i=current=4A.
As E-ir=iR=V,
n^2-n=2 x nCr.
this is possible only when r=2 and n-2 because nCr=nCn-r.
nCr=n!/((r)!(n-r)!).