Three gunmen shoot at a target and hit it in an average of 1 for every 4 attempts. If the three gunmen fire simultaneously, what is the probability, in percentage, that the target be hit in 1 attempt?
Based in ITA, a institute from Brazil :)
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The probability that they will FAIL will be:
3/4 * 3/4 * 3/4 = 0.421875} = 42.1875%
The solution will be 100% less this:
100% - 42.1875%= 57.8125%