Is 2 0 6 0 1 9 5 8 divisible by 13?
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Here utilizing the rule of 13s.
We can't use the calculator but we can still use the scratchpad!
I divided it by mind.. Please, tell me the short cut method to solve it...
Multiply each digit starting from right to left with the numbers.. 1 , 1 0 , 9 , 1 2 , 3 , 4 , in cycle, i.e.
Like this... The NO. 2 0 6 0 1 9 5 8 What We Do : 8 × 1 + 5 × 1 0 + 9 × 9 + 1 × 1 2 + 0 × 3 + 6 × 4 + 0 × 1 + 2 × 1 0 = 1 9 5 We see, 195 is divisible by 13 hence the result.
Also for last no. we got if it leaves a remainder 9 then also it is divisible by 13.
Arya :)
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I didn't got the second step i.e 8 x 1+... . Please explain in more detail..
check out by method
Yep, I did the same thing. Didn't know the divisibility test for 13.
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Add four times the last digit to the remaining leading truncated number. If the result is divisible by 13, then so was the first number. Apply this rule over and over again as necessary. (generally end when number become less than 130) like:- 2060195+8x4=2060227 and 206022+7x4=206050 and 20605+0x4=20605 and 2060+5x4=2080 and 208+0x4=208 and 20+8x4=52 and 52/13=4 hence given number is divisible