Do the double dance!

The difference is in Arithmetic Progression of 5.

plus 5 to every difference

2, 2+(9) = 11, 11+(9+5)=25, 25+(9+5+5)=44, 44+(9+5+5+5)=68, 68+(9+5+5+5+5)= 97...

The sequence 2, 11, 25, 44, 68 has a common sequence of 9, 14, 19, 24. Thus the next sequence would be 29, 34, 39,... 68+29 gives 97.

11-2=9، 25-11=14، 44-25=19 ، 68-44=24 ، 14-9=19-14=24-19=5 ،، X-68=5 ،، X=97

Finding the difference like : 11 -2 = 9 similarly you will get : 9 , 14, 19, 24 , observe the difference is 5 hence Arithmetic Series Using Arithmetic formula : Un = a + (n-1)d Or 19 +5 = 24 ,, 68 + 29 = 97

It is a progression in which the differences are in AP with common difference= 5...

THE ANSWER IS 97 AS THE DIFFERENCE BETWEEN CONSEQUITIVE NUMBERS INCREASES BY 5

11-2=9, 25-11=14, 44-25=19, 68-44=24, x - 68 =29 or, x=97

this sequence can be generated using the following recursive relation :

N(t) = N(t-1) + [ (5*t ) - 1 ] where t >=1

the code for this in C++ as follows :

int seq( int t){ if(t==1) return 2; else return seq(t-1) +(5*t-1); }

the difference between each number in sequence is simply an Arithmetic Progression of common difference of 5... $a_1=11-2=9$ $a_2=25-11=14$ $a_3=44-25=19$ $a_4=68-44=24$ the common difference is $d=a_4-a_3=24-19=5$ , or $d=a_3-a_2=19-14=5$ , and so on... therefore for $a_5=9+4\times5=29$ and for the next number in the sequence, it will be $68+29=97$

25-2=23,68-25=43 so 43-23=20 44-11=33 so 33+20=53,44+53=97

the difference of the numbers, has a common difference of 5.

it is an AP of AP

Find difference between these numbers 2,11,25,44,68......=>9,14,19,24 in this series the difference 5.SO, add 5 to 24 we get 29 and add 29 to 68 we get 97.

their difference is in A.P

The differences are in AP with a common difference of 5

use difference method

pattern is 9,14,19,24,29

so answer is 68+29=97

97 , +5with every differences

The difference is in Arithmetic Progression by 5.

2 + (4 + (1 x 5)) = 11 ----> 11 + (4 + (2 x 5)) = 25 ----> 25 + (4 + (3 x 5)) = 44 ----> 44 + (4 + (4 x 5)) = 68 ----> 68 + (4 + (5 x 5)) = 97

2, 11 difference 9. 11,25 diff 14. 25,44 diff 19 44,68 diff 24. So 9,14,19,24 common increase 5. so next 29. 68+29=97

the pattern is 14,19,24,29. arithmetic sequence and progreession

difference is a series like 9,14,19,24,29..............

2,11,25,44,68..... by using arithmetic pattern in first there is 9 difference then 14,19,24,29 therfore 2+9=11,11+14=25 similarly 68+29=97

2 11 25 44 68 {97} the diff. b/w 9 14 19 24 29 you can get the trick by just seeing the difference and order by which it changes

+9, +14, +19, +24, +29

97.....2+23=25;11+33=44;25+43=68;44+53=97

The difference in every 2 number increases 5..

Here 2+9=11 11+(9+5)=11+14=25 25+(14+5)=25+19=44 44+(19+5)=44+24=68 68+(24+5)=68+29=97

Thus the solution is 97.

just add 5 to every difference

The differences are 9,14,19,24. So, the next difference will be 29. Thus the answer is 68+29=97

The differences are 9,14,19,24. So, the next difference will be 29. Thus the answer is 68+29=97

Bilangan bertingkat

the sequence is 9,14,19,24,so then the next no. is 29

The diff in the nos. is an A.P. with C.D.=5

The series 2, 11, 25, 44 and 68 has a common sequence of 2, 14, 19, 24 with a distinctive difference of 5, therefore, after 68 following the sequence of 24+5 = 29, so the next after 68 = 68 + 29 = 97..

11-2=9: 25-11=14 : 44-25=19 ; 68-44=24 : ans= (9,14 ,19,24, similarly 29) 68+29= 97