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A ball with the initial velocity u = 3 i + 4 j u = 3i + 4j collides with the smooth wall and rebounds with the final velocity v = 2 i 3 j v = 2i - 3j . Find the coefficient of restitution for the collision.


Your answer can be represented as e e = a b \dfrac{a}{b} , where a and b are coprime numbers.

Enter your answer as a + b a + b .


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This is a part of my set Aniket's Mechanics Challenges . (All level questions)


The answer is 50.

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3 solutions

Aniket Sanghi
Mar 19, 2016

First find the vector for change in velocity. This gives you the direction of impact. Now find the components of initial and final velocity about this direction by taking dot product. Their ratio gives you e.

Oh ya! By your method the solution will become quite small. Actually I did the long way! I considered a unit vector n ^ = c o s θ i ^ + s i n θ j ^ \hat{n} = cos\theta \hat{i} + sin\theta \hat{j} representing the normal along the line of impact between the body and the wall. I then equated the magnitudes of the components of u \vec{u} and v \vec{v} perpendicular to n ^ \hat{n} as velocity of the body shall change only along the line of impact. From this, I got the value of t a n θ tan\theta . Now the ratio v . n ^ u . n ^ \large \frac{\vec{v}.\hat{n}}{\vec{u}.\hat{n}} gives you the value of e

Miraj Shah - 5 years, 2 months ago

Bhaiyya this is mains or advanced level? I just encountered this problem in my mains practice paper.

Swapnil Das - 3 years, 8 months ago

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We can say it mains level from the length of sol and the level of q

Aniket Sanghi - 3 years, 8 months ago
Amrit Anand
Apr 18, 2016

It is a bit long!

Aniket Sanghi - 5 years, 1 month ago
Mayank Singh
Apr 6, 2016

Let n n represent the unit vector along the normal to wall, u u the initial velocity vector and v v the final velocity vector.

Since the velocity component along the wall remains same, we have

u u X n n = v v X n n

= > ( u u - v v ) X n n = 0

= > n n =k( i i +7 j j )

To find - u . n v . n \frac{u.n}{v.n} = 19 31 \frac{19}{31}

Very nice explanation

space sizzlers - 4 years, 11 months ago

Same way...well explained

rajdeep brahma - 3 years, 2 months ago

Same method

A Former Brilliant Member - 5 years, 2 months ago

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