A calculus problem by Star Fall

Calculus Level 5

How many of the following statement(s) is/are wrong ?

  1. The pointwise limit of a sequence of continuous functions is continuous.
  2. Every continuous function defined on closed real intervals is Riemann integrable .
  3. Real power series are uniformly convergent within compact subintervals of their interval of convergence .
  4. Every real-valued smooth (infinitely differentiable ) function admits a Maclaurin series expansion which converges to the function on some open subset of its domain.
  5. A convergent series whose terms are differentiable functions of x can always be differentiated termwise to obtain the derivative of the limit function.
3 2 1 4 0

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1 solution

Star Fall
Jul 2, 2016

The incorrect statements are #1, #4 and #5.

A counterexample to 1 is the sequence of functions f n ( x ) = x n f_n(x) = x^n on the interval [ 0 , 1 ] [0, 1] . The pointwise limit, as is easily checked, is not continuous.

4 is correct for complex-valued smooth (holomorphic) functions, but it is false for real-valued smooth functions: consider the function f ( x ) = e 1 / x 2 f(x) = e^{-1/x^2} . It is easy to check that every derivative of f ( x ) f(x) vanishes at x = 0 x = 0 , but f f is not identically zero, whereas its Taylor expansion turns out to be.

5 requires uniform convergence of the series, in general, it is true for power series within their interval of convergence. However, it is not generally true; consider the sum of sin ( k x ) / k \sin(kx)/k as k k ranges over the positive integers. This sum is convergent to a differentiable function (this is a well known fact), but termwise differentiation gives something which does not even converge.

"2" is also false. A function needs to be differentiable in order to be integratable. If said function is smooth, there are no issues, but if there's spikes, or other such points, even though the function remains continuous, still technically cannot be integrated.

John Dye - 4 years, 11 months ago

No, it is not false. Read Lebesgue's integrability criterion for the Riemann/Darboux integrals: See this .

Star Fall - 4 years, 11 months ago

Number 5 requires uniform convergence of the sequence of derivatives, not just the sequence itself. It is easier to give a suitable example as a sequence, not a series. Consider f n ( x ) = sin n x n f_n(x) = \frac{\sin nx}{\sqrt{n}} . Then f n ( x ) 0 f_n(x) \to 0 uniformly on R \mathbb{R} , but f n ( x ) f_n'(x) fails to converge anywhere...

Mark Hennings - 4 years, 11 months ago

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