Do you know differentiation?

Calculus Level pending

Let f ( x ) = x + sin x f(x) = x+ \sin x and g ( x ) = f 1 ( x ) g(x) = f^{-1} (x) . Find g ( 2 π ) g'(2\pi) .

1 2 \frac12 1 3 \frac13 1 4 \frac14 1 1

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1 solution

Tanmay Sinha
Jun 3, 2016

let f-1(x)=g(x)

x=f(g(x))

differentiating both sides w.r.t. x

1 = f '(g(x)) * g'(x)

g'(x) = 1/f'(g(x))

Now , let g(2π)= f-1(2π) = p

therefore f(p) = 2π

hence p = 2π as f(x) =x+sinx

therefore g(2π)=2π

g'(x)=1/f'(2π)

f'(2π) = 2

hence 1/f'(2π) = 1/2 .

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