Do you know topology? 2 "Analysis Situs"

Let the sphere S 2 = { ( x , y , z ) R 3 ; x 2 + y 2 + z 2 = 1 } \mathbb{S}^2 = \{(x,y,z) \in \mathbb{R}^3 ; x^2 + y^2 + z^2 =1 \} and the torus T 2 = { ( x , y , z ) R 3 ; ( x 2 + y 2 a ) 2 + z 2 = r 2 and a > r > 0 } \mathbb{T}^2 = \{(x,y,z) \in \mathbb{R}^3 ; (\sqrt{x^2 + y^2} - a)^2 + z^2 = r^2 \text{and } a > r >0\} .

Which statements below are true?

a) There exists an homeomorphism from S 2 \mathbb{S}^2 to T 2 \mathbb{T}^2

b) There exists an homeomorphism from S 2 \mathbb{S}^2 to R 2 \mathbb{R}^2

Details and assumptions :

The topology used in each space is the euclidean topology

Both (a) and (b) (b) Neither (a) nor (b) (a)

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

a) S 2 is simply connected and T 2 isn’t simply connected \mathbb{S}^2 \text{ is simply connected and } \mathbb{T}^2 \text{ isn't simply connected} and simply connectedness is an unvariant under homeomorphisms(bijective continuous function)... (we can also say that they have distinct fundamental groups or Euler's Characteristic are distinct (Vertex -Edges + Faces = χ \chi ; χ ( S 2 ) = 2 ; χ ( T 2 ) = 0 \chi(\mathbb{S}^2) = 2 ; \chi(\mathbb{T}^2) = 0 and group fundamental an Euler characteristic are topological invariant...) EULER CHARACTERISTIC

b) S 2 is a compact set (with euclidean topology it is closed and bounded) and R 2 isn’t it \mathbb{S}^2 \text{ is a compact set (with euclidean topology it is closed and bounded) and } \mathbb{R}^2 \text{ isn't it} and compactness is an unvariant under homeomorphisms

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...