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Classical Mechanics Level 1

A load of 300 k g 300 kg is pulled up by 5 m 5 m , then calculate the work done by the pulling force( in Joules).

Please take the magnitude of acceleration due to gravity = 9.8 m/s 2 9.8 \text{ m/s}^2


The answer is 14700.

Swapnil Das by Swapnil Das , 20, India

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4 solutions

Rama Devi
May 14, 2015

Work =mass X acceleration due to gravity X height = 300 X 5 X 9.8 =14700 joule

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Sarthak Rath
May 13, 2015

we apply a force of m × g m \times g to lift up.

so work done is equal to m g h mgh

putting values, m= 300 k g 300kg , g= 9.8 m s − 2 9.8ms^{-2} and h = 5 m 5m ,

work done = 14700 J \boxed{14700 J}

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Ok this one was quite unfair.You should have mentioned that g = 9.8 m s − 2 g=9.8ms^{-2} I used the approximation g = 10 m s − 2 g=10ms^{-2} and input 15000...

Arian Tashakkor - 6 years, 1 month ago

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Thanks, I have edited the problem!

Swapnil Das - 6 years, 1 month ago
Sooraj Vijay
May 29, 2015

The answer should be -14700. Since force is in the opposite direction of displacement. i.e. We are doing work against gravity.

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potential energy = work done = mgh

WORK DONE=300 5 9.8=14700J

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Good Job! Keep Posting!

Swapnil Das - 6 years, 1 month ago

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