Do you like ellipse?

Geometry Level 4

Let k k be the ratio of the area of an ellipse A e A_e to the area of the triangle A t A_t the ellipse is inscribed in; that is: k = A e A t . k=\dfrac {A_e} {A_t} .

Given that the maximum value of k k has a closed form, find this closed form.

Submit your answer to 2 decimal places.


The answer is 0.60.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

3 solutions

Mehul Kumar
Jun 6, 2016

Project the plane such that the ellipse becomes the circle, in this projection ratio of areas are invariant!
k = ( π r 2 Δ ) = ( π Δ 2 s 2 Δ ) = ( π Δ s 2 ) \\ \implies k= (\frac{\pi r^2}{\Delta} ) =(\frac{\pi \Delta^2}{s^2 \Delta} ) =(\frac{\pi \Delta}{s^2})
w.l.o.g assume s=1 \implies a+b+c=2
π Δ = π ( ( 1 a ) ( 1 b ) ( 1 c ) ) π ( ( 1 a ) + ( 1 b ) + ( 1 c ) 3 ) 3 2 = π 3 3 u s i n g A M G M \implies \pi \Delta= \pi \sqrt((1-a)(1-b)(1-c)) \leq \pi (\frac{(1-a)+(1-b)+(1-c)}{3})^\frac{3}{2} = \frac{\pi}{3\sqrt3} \space using \space AM-GM M A X k = π 3 3 0.60 \\ \implies MAX \space k = \frac{\pi}{3\sqrt3} \approx 0.60


Can you please give a more detailed solution ! Thanks.

Niranjan Khanderia - 5 years ago

link text
This is known as Steiner_inellipse and the above link gives us that the ratio is π 3 3 . \dfrac \pi {3\sqrt3}.
This link is from my solution to almost the same problem "Medial Ellipse" by Sharky Kesa, just two days back.

Maria Kozlowska
Jun 6, 2016

The ellipse is Steiner inellipse . The ratio is π 3 3 0.60 \dfrac{\pi}{3\sqrt{3}}\approx \boxed{0.60}

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...