Doctor! Doctor!
A doctor is called to see a sick child. The doctor knows (prior to visit) that 90% of the children in that neighborhood are sick with flu while 10% are sick with conditional probability 0.08.
Upon examination of the child, doctor finds a rash. What is the probability that the child has measles?
If the answer is of the form where and are coprime positive integers, find .
The answer is 262.
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1 solution
using Baye's theorem: P = .95 × .10 / (.95 × .10 + .08 × .90) P = 95/167 = a/b a + b = 95 + 167 = 262