Does commutative property apply?

Geometry Level 3

A = sin [ sin ( 1 ) ] B = sin [ cos ( 1 ) ] C = cos [ sin ( 1 ) ] D = cos [ cos ( 1 ) ] A = \sin\left[\sin(1)\right] \\ B = \sin\left[\cos(1)\right] \\ C = \cos\left[\sin(1)\right] \\ D =\cos\left[\cos(1)\right]

The above are the values of A , B , C , A,B,C, and D . D. Which of the answer choices is true?


Clarification: All angles are measured in radians.


Inspiration .

B < C < A < D B < C< A < D D < A < B < C D < A < B < C A < D < C < B A < D < C < B C < B < D < A C < B < D < A

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1 solution

Hitesh Yadav
Jul 14, 2020

Can do by doing back and forth between degrees and radians by approximating. s i n ( s i n ( 1 ) ) = s i n ( s i n ( 5 7 ) ) sin(sin(1))=sin(sin(57^{\circ} )) And then B was s i n ( c o s ( 1 ) ) sin(cos(1)) which is the same way of saying s i n ( c o s ( 5 7 ) ) sin(cos(57^{\circ})) and since sine of 57 degrees is greater than cosine of 57 degrees thus A will be greater than B which is the case in only two options , namely option A and option D. And the only difference between the options is whether D is greater than or smaller than A. By applying the same methodology we can get the answer

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