n = 1 ∑ ∞ n n 1
Evaluate the summation above to three decimal places.
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Correct. Note that this summation is derived from Sophomore's dream thus the slightly subtle title to this problem.
It is clear that the infinite sum converges because : n = 1 ∑ ∞ n n 1 < n = 1 ∑ ∞ n 2 1 = 6 π 2 ≈ 1 . 6 4 The first 7 terms produces 1.291 to 3 significant figures
Problem Loading...
Note Loading...
Set Loading...
Note that the successive the terms in the series rapidly converges to zero. As an estimate, we have n = 6 ∑ ∞ n n 1 ≤ ∫ x = 5 ∞ x 6 1 d x = 1 5 6 2 5 1 = 0 . 0 0 0 0 6 4 Hence to obtain a result correct upto the third term of the decimal, it suffices to compute the partial sum of the series only up to the first 5 terms, which evaluates to 1.291.