Does this look familiar?

Calculus Level 4

( e x 2 2 2 π ) d x \large \int_{-\infty}^{\infty} \left( \dfrac{e^{\frac{-x^2}{2}}}{\sqrt{2\pi}} \right) dx

If the value for the above integral is A A , find the value of b b such that

b b ( e x 2 2 2 π ) d x = 0.9 A \large \int_{-b}^{b} \left( \dfrac{e^{\frac{-x^2}{2}}}{\sqrt{2\pi}} \right) dx = 0.9A .

Give the answer to the nearest 3 decimal places.


The answer is 1.645.

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1 solution

Abhishek Sinha
Dec 11, 2015

The variable b b is simply the 95 95 th percentile of the standard normal distribution.

Exactly. That's basically how it works.

Worranat Pakornrat - 5 years, 6 months ago

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https://en.wikipedia.org/wiki/Normal_distribution

To save from doing hard work, I simply refer to the above.

Lu Chee Ket - 5 years, 5 months ago

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