A four digit number has the following properties:-
a) It is a perfect Square
b)It's first two digits are equal to each other
c) It's last two digits are equal to each other.
Find the sum of all four digit numbers which satisfy.
Details and assumptions
If you think that no such numbers exist, Input 0.
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Let the number be a a b b
We know 1 0 0 2 = 1 0 0 0 0 , Hence, The number has to be a two digit number
From the divisibility rules of 11, we get to know that this number is divisible by 11.
We also know from the given criteria, That the number is a perfect square.
Hence, The number has to be in the form of:- 1 1 2 × a 2 Where 0 > a > = 9
We list out all such numbers.
1 2 1 × 1 = 1 2 1
1 2 1 × 4 = 4 8 4
1 2 1 × 9 = 1 0 8 9
1 2 1 × 1 6 = 1 9 3 6
1 2 1 × 2 5 = 3 0 2 5
1 2 1 × 3 6 = 4 3 5 6
1 2 1 × 4 9 = 5 9 2 9
1 2 1 × 6 4 = 7 7 4 4 < Satisfies the Criteria
1 2 1 × 8 1 = 9 8 0 1
Hence, The only number which satisfies the conditions is 7744.
Answer:- 7 7 4 4