A small green circle is inscribed within the section of a bigger blue circle, touching the mid-chord, as shown above left. Then the graphs are revolved around the -axis to generate three figures: a blue cover dome, a green spherical melon, and a red serving plate.
Which of the following options will have more surface area?
I. The blue dome
II. The melon plus the plate
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Let R be the radius of the big circle; r be the radius of the red plate; and h be the diameter of the green sphere.
It is obvious that the red circular area = π r 2 and the surface area of the green sphere = 4 π ( 2 h ) 2 = π h 2
Now in order to calculate the spherical section area of the blue dome, we need to find out the radius of the original full sphere, R in terms of r and h :
According to the diagram above, by using Pythagorean theorem, R 2 = ( R − h ) 2 + r 2 .
Thus, 2 R h = h 2 + r 2 .
Hence, R = 2 h h 2 + r 2 .
Now according to Archimedes' Hat-Box Theorem , any spherical section from spherical radius R and of height h will have its lateral surface area equal to the lateral surface area of a cylinder of radius R and height h :
That is, the spherical section area = 2 π R h = π ( 2 h ) 2 h h 2 + r 2 = π ( h 2 + r 2 ) .
Thus, clearly the surface area of the blue dome = surface area of a green sphere + red circular plate.