Polygon and it's sides

The sum of exterior angles is 360° 360 - (72+35) = 253° 253/23 = 11 angles of 23° 11 + 2 = 13 sides n = 13

The sum of exterior angle of a polygon is $360^\circ$ . Let $x$ be the number of exterior angle that measures $23^\circ$ , then

$72+35+23x=360$

$23x=253$

$x=11$

Therefore, the number of sides is $11+2=$ $\boxed{13}$ .

Sum of exterior angles is $360^{\circ}$ . Let there be n sides. So $n-2$ angles are $23^{\circ}$ . Thus $360=23 (n-2)+72+35$ . Solving we get $n=13$ .

by finding the supplementary angles of the exterior angles given
we get sum of those 2 interior angles to be 253 WKT , no. of angles = no. of sides

sum of iterior angles of a n-gon is (n-2)*180

it is given that all other exterior angles are 23 degrees so all other interior angles must be 157

now ,

253+157(n-2) = (n-2)*180

by further simplification we get "n" as 13