A box of maximum volume with top open is to be made by cutting out four equal squares from four corners of a square Aluminium sheet and then folding up the flaps. The square aluminium sheet has the side length .
If the side length of the square cut-off can be represented as , find .
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Volume of the box so formed is y ⋅ ( x − 2 y ) 2 = V .
As V is a function of y , we can set its derivative equal to zero for the maxima. d y d V = 0 ⟹ ( x − 2 y ) 2 ⋅ 1 + y ⋅ 2 ⋅ ( x − 2 y ) ⋅ ( − 2 ) = 0 (Using Product Rule) ⟹ x = 6 y Now y = x / 6 = 9 7 x / n . Solving yields n = 9 7 × 6 = 5 8 2