Don't be afraid , take an attempt :-

$\frac{dy}{dx}$ $-$ $2y$ = $3e^{x}$

the above equation is a linear differential equation with i.f. $=$ $e^{-2x}$

hence its solution is $ye^{-2x }$ $=$ $-3e^{-x}+c$

since it is given that at $x=0$ , $y=0$

therefore, $c=3$

now the solution of the differential equation is $ye^{-2x}$ = $-3e^{-x}$ $+$ $3$

putting $x = ln2$ , we get $y = 6$

therefore $\frac{y(ln2)}{12} = \frac{6}{12} = 0.5$