A ladder with a length of four meters is placed against a wall. The ladder touches the box of one by one meter, which is standing against the wall. At what height does the top of the ladder touch the wall?
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Let ABC be the triangle with angle ABC 90 degrees. Let BDEF be the square.
Let x be the length of line segment AD, and let y be the length of line segment CF.
1)Because of the similarity of the triangles ADE and EFC, the following holds: x:1=1:y
So xy=1 . Also x=1/y and y =1/x
2)(x+1)^2 + (y+1)^2 = 4^2
(x^2+2+y^2) + 2x+2y=16
Using xy=1,
(x^2+2xy+y^2) +2x +2y=16
(x+y)^2 +2(x+y)-16 =0.
Solving quadratic equation (x+y) = 3.123
3)x=1/y so x+(1/x)= 3.123
x^2+1= 3.123x
x^2-3.123x+1=0
Solving quadratic equation,
x= 2.76
The height of wall where ladder touches is 2.76 +1= 3.76