A disk of mass and radius is pushed up on an inclined plane of angle with initial speed . If and the coefficient of friction is such that the disk can roll without slipping, the maximum height reached by the disk can be expressed as . Find .
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At first we have kinetic energy and rotational kinetic energy of a disc, so we have: E 0 = 2 m v 2 + 2 I ω 2 = 2 m v 2 + 2 ⋅ 2 r 2 m r 2 v 2 = 4 3 m v 2 At maximum height we have: E f = m g h As energy conservates: E f = E 0 m g h = 4 3 m v 2 h = 4 g 3 v 2 = 4 0 3 v 2