The number 27000001 has exactly 4 prime factors.
Find their sum.
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2 7 0 0 0 0 0 1
= 3 0 0 3 + 1 3
= ( 3 0 0 + 1 ) ( 3 0 0 2 − 3 0 0 + 1 )
= 3 0 1 ( ( 3 0 0 + 1 ) 2 − 3 ⋅ 3 0 0 )
= 3 0 1 ( 3 0 1 2 − 3 0 2 )
= 3 0 1 ( 3 0 1 − 3 0 ) ( 3 0 1 + 3 0 )
= 3 0 1 ( 2 7 1 ) ( 3 3 1 )
= 7 ⋅ 4 3 ( 2 7 1 ) ( 3 3 1 )
so the answer is 7 + 4 3 + 2 7 1 + 3 3 1 = 6 5 2 .