Compute the sum of the distinct prime factors of the number 1 0 0 7 0 2 1 0 3 5 0 3 5 0 2 1 0 0 7 0 0 1
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Notice the 'main' numbers:
1 − 7 − 2 1 − 3 5 − 3 5 − 2 1 − 7 − 1
These are from pascal's triangle!!
Since there are 2 zeros in between each pairs of numbers we have:
1 0 0 1 7 as the number in the question.
It is a well known fact that 1 0 0 1 = 7 ⋅ 1 1 ⋅ 1 3 so we have the required sum as 7 + 1 1 + 1 3 = 3 1
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The number can be rewrtitten as ( 0 7 ) 1 0 0 0 0 + ( 1 7 ) 1 0 0 0 1 + . . . + ( 7 7 ) 1 0 0 0 7 = ( 1 0 0 0 + 1 ) 7 = 7 7 × 1 1 7 × 1 3 7 Thus:7+11+13=31