The mass of an elephant can be many thousands of kilograms and their feet can be over a meter around. If a 6 0 0 0 kg elephant is standing and its feet each have a circumference of 1 . 3 4 m , how much pressure in pascals does one foot exert on the ground? The pressure, for those who may be unaware, is the total force exerted divided by the area over which the force is exerted, i.e. p = F / A .
Details and assumptions
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force exerted by elephant=9.8 x 6000=58800
area in which force is distributed=4 x area of 1 foot
pi x d=1.34 (d=diameter of a foot)&&(pi=3.14)
so (((pi x d)^2)/4 x pi)=area of 1 foot((pi x (d^2))/4)
area of 4 foot=4
(((pi
d)^2)/4*pi)=((((1.34)^2) / 3.14))=0.571557
preasure=force/area=58800/0.571557=102877
From p = F/A, we know that we have to find 2 values, the total force exerted by the elephant's feet and the total area of the elephant's feet.
From Newton's Second Law of Motion, F = ma Also, from Newton's Third Law of Motion, For every action force, there must be an equal but opposite reaction force. Thus, total force exerted by the elephant's feet which is supporting the elephant is F = 6000 x 9.8 = 58800 N
Then, we proceed to find the area of the elephant's feet. Circumference of foot: (pi) (2r) = 1.34m Radius of foot: r = 0.21326762374 m Area of 4 feet: 4 (pi) (r)^2 = 0.57155723161 m^2
Thus, by p = F/A, Pressure that one elephant foot exerts on the ground = p = 58800 / 0.57155723161 = 102876.8 Pa = 102877 Pa (Nearest whole number)
Mass of the elephant = 6000 kg
Weight = m g = 6000 X 9.8 = 58800 N
Let the radius of each of the elephant's foot be r
Circumference of each foot = 2 π r = 1.34m Therefore, r = 0.213267 m
Area of each foot = π r 2 = 0.14288 m 2
Total area = 4 X 0.14288 = 0.57155 m 2
Pressure = 0 . 5 7 1 5 5 5 8 8 0 0 = 102878.2
We know that, F = m a ⟹ W = m g
Plugging in the mass 6 0 0 0 k g and the acceleration of gravity 9 . 8 m / s 2 , we get,
6 0 0 0 k g × 9 . 8 m / s 2 = 5 8 8 0 0 N
We assume that, the weight is distributed evenly between the four feet... So, the amount of force one foot exerts is, 4 5 8 8 0 0 N = 1 4 7 0 0 N
So, we found one of the value, F , needed to find the pressure...
Next, it's given that the circumference of one foot is 1 . 3 4 m ...
We can rewrite, 2 π r = 1 . 3 4 m ⟹ r = 2 π 1 . 3 4 m = π 0 . 6 7 m
Now, we work out the area, π r 2 = π × ( π 0 . 6 7 ) 2 m 2 = π × π 2 0 . 4 4 8 9 m 2 = π 0 . 4 4 8 9 m 2
OK, now we have both of the two values to find the pressure... Let's plug in...
p = A F = π 0 . 4 4 8 9 m 2 1 4 7 0 0 N = 0 . 4 4 8 9 1 4 7 0 0 π k g / m = 1 0 2 8 7 7 k g / m (approx.)
Hence, the required value is 1 0 2 8 7 7 ...
Solve using (6000/4*9.8) / ((1.34 / pi / 2)^2 * pi) aka the p = F / A formula
A = the area of a circle, given the circumference of each feet
F = mass (acceleration), given the mass of each foot (6000/4) and gravity.
I converted the kilograms to Newtons, divided by the total area of the feet combined, then divided by 4.
r=(1.34/(2)*(pi))
area of one foot=(pi) (r) (r)
net area = (4) (pi) (r)*(r)
net force = (m)*(g)
pressure=net force/netarea=(mg)/((pi) (r) (r))=102877
Given for one foot: 2( 3.14 ) r = 1.34.........Curcumference
Thus: 3.14 ( r ^ 2 ) = 0.1428893.......................Area of Single Foot
Thus Total Area = 0.571557231.......................Area of all 4 feet
Force=Mass*Acceleration
=> 6000 * 9.8
Thus Pressure=F/A
=> 6000 * 9.8 / 0.571557231
Answer=102877 Pascal
Circumference = 2 pie r = 1.34 from here we got the value of 'r' . Then Area =4 pie r^2 [multiplied 4 because it has four legs ;) ] !!! Force=m a = 6000 9.8 !! so Pressure = F/A DONE :D Please ask if any doubt !!!!
With given circumference , find the area of each foot . Then calculating the gravitational force (mass x acceleration due to gravity) divide it by the area . Here we get the pressure on each foot .
We know, circumference = 2 pi r = 1.34m so r= 0.213; Area of circle(are of each leg), A= pi r r; And F=ma , where m=mass, a=gravity; So force exerted by four leg, x =F/A; SO force exerted by four leg, p= x/4 ; which is 102877.396
Since Pressure = Force / Area, we can find force to be the weight of the entire elephant , which is 6 0 0 0 × 9 . 8 = 5 8 8 0 0 N
Then we can find the area that elephant is standing on, which is circular, to be ( 2 P i 1 . 3 4 ) 2 × P i = 0 . 1 4 2 8 8 9 m 2
Divide the force by the area to find:
0 . 1 4 2 8 8 9 5 8 8 0 0 = 4 1 1 5 0 7 P a
However, since the question asks for the pressure of one foot on the ground, we must divide by 4 to find that the answer is:
4 4 1 1 5 0 7 = 1 0 2 8 7 7 P a
As stated, we compute for the pressure which is the Force over the Area.
Solving for the Force, it is simply the product of the mass and the acceleration (in this case the gravity) so F = m a = 6000 kg \times 9.8 s 2 m = 58800 N
For the Area, it is simply π r 2 , since we are given the circumference we can solve for r: We get r = 2 π C = 2 π 1 . 3 4 m = 0.21 m
So the Area is given by: A = π ( 0 . 2 1 2 ) = 0.14 m^{2}
Then the total Pressure is given by: p = A F = 0 . 1 4 m 2 5 8 8 0 0 N = 411507 m 2 N
F = m * g = 6000 x 9.8
We know that, elephant has 4 legs.. Because of that : The circumference of elephant's leg = 2 x 3.14 x r = 1.34
r = 1.34 / ( 2 x 3.14 )
So : A = 4 x ( 3.14 x r ^2)
So that, P = F/A = 102877
1KG=9.81 NEWTON 6000KGX9.81 NEWTON=58860 NEWTON 58860/4=14715 NEWTON FOR EACH LEG CIRCUMFERENCE= 3.1415XD 1.34=3.1415XD DIAMETER=0.427 METER AREA=3.1415/4X(0.427)^2 AREA=0.143 M^2 p=f/a p=14715 newton/(3.1415/4x(0.427)^2=102757.762 pascal or 102.902 kpa
There F(force) = 6 0 0 0 ∗ 9 . 8 = 5 8 8 0 0 k g . m / s 2 ;
Radius of the 1 feet of the elephant = r = 1 . 3 4 ∗ 7 / 2 ∗ 2 2 = 0 . 2 1 3 1 cm ;
Area of 1 feet of the elephant = 2 2 ∗ 0 . 2 1 3 1 2 / 7 = 0 . 1 4 2 6 c m 2 ;
So, A(area of 4 feet) = 4 ∗ 0 . 1 4 2 6 = \(0.571)\ cm^2
Then F/A = \(58800/0.571\) = 1 0 8 7 7 . 2 3 2 9 p
ans will b 102797
there is a typing mistake i want to write 1 0 2 8 7 7 . 2 3 2 9 p instead of 1 0 8 7 7 . 2 3 2 9 p
F = mg = 6000 9.8 Area= pi * r^2 where 2 pi* r =1.34 from this area = 0.14288 m^2 therefore P=F/A P=6000*9.8/0.14288 But this is the pressure exerted by all 4 feet, to get pressure for one feet we divide the total pressure by 4.
Therefore P= (6000*9.8/0.14288)/4 P =102883.5386
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First of all calculate the radius of the feet of the elephant using the formula 2 pi r=1.34 m, and then find out area of the feet by pi r^2. now calculate the weight of elephant,mg=6000 9.8 Newton, this will be uniformly distributed over four legs and hence effective mass on one leg will be total mass/4. devide this wieght(force) by contact area(area of the elephant's feet) and get the result.