+ n + 41 is prime for every natural number n.
Is this statement true, or false?
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First we will take a factor of n from the first two terms of the expression. Leaving us with:
n(n+1)+41
We will work with this now to prove several things. The first is that the statement from the problem is false. We can do this through a counter example: substituting n for 41, we have:
41(42)+41 = 41(42+1)
Which is not a prime number, and since 41 is a natural number, then the statement is false . As we can see, this would also be true for n = 40 (Because n + 1 = 41, thus the whole expression is a multiple of 41, and not prime.) With the problem solved, we could also look for the cases in which the expression is not prime. It is easy to see that, since 41 is prime, the only time n(n+1) and 41 are going to have any factors in common is if either n, or n+1 are a multiple of 41. This is why it is a nice problem for beginner mathematicians. Because they won't be able to try and test with different values for n, because the first number that will not make the expression prime is 40.