Don't make mistakes! #7

Algebra Level 3

There is a watermelon that weighs 990 g . 990\text{g}.

A <Very Precise Moisture Analyzer> indicates that 99 % 99\% of this watermelon's mass is water.

Then you decide to put this watermelon under a warm daylight.

After a few days, you pick up the <Very Precise Moisture Analyzer> and it indicates that only 98 % 98\% of the dehydrated watermelon's mass is water.

What is the mass of the dehydrated watermelon?

Details and assumptions:

  • The <Very Precise Moisture Analyzer> is very precise.

  • The watermelon did not decay.

  • Only water vaporizes from the watermelon when you put it under sunlight.

This problem is a part of <Don't make mistakes!> series .

330g 980g 979.902g 247.5g The given information is insufficient 495g 990g 660g

Boi (보이) by Boi (보이) , 19, South Korea

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1 solution

Boi (보이)
Jul 25, 2017

The most important thing to do is to figure out that the non-water part (=flesh, rind, seeds) of the watermelon doesn't change throughout the dehydration.

The non-water part of the original watermelon is 990 g × 0.01 = 9.9 g . 990\text{g}\times0.01=9.9\text{g}.

The non-water part of the dehydrated watermelon is 0.02 w g . 0.02w~\text{g}.

Therefore, 0.02 w = 9.9. 0.02w=9.9.

w = 495 , w=495, and thus, the dehydrated watermelon has a shocking mass of 495 g . \boxed{495\text{g}}.

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