Don't Overcomplicate this problem.

Calculus Level 4

I 1 = ∫ 0 x e z x e − z 2 d z I 2 = ∫ 0 x e − z 2 4 d z \large I_{1} = \displaystyle \int_{0}^{x} e^{zx}e^{-z^2}dz \qquad \qquad I_{2} = \displaystyle \int_{0}^{x} e^{\frac{-z^2}{4}} dz

For I 1 I_1 and I 2 I_2 as defined above, which of the following is true?

Try my set
I 1 = e x 2 4 × I 2 I_1 = e^{\frac{x^2}{4}} \times I_2 I 1 = e x 2 × I 2 I_1 = e^{x^2} \times I_2 I 1 = e x 2 2 × I 2 I_1 = e^{\frac{x^2}{2}} \times I_2 I 1 = e x × I 2 I_1 = e^x \times I_2

Vishwak Srinivasan by Vishwak Srinivasan , 24, India

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1 solution

Kushal Bose
Sep 10, 2016

Just put 2 z = t + x 2 z=t+x as t t as variable.

Nice problem

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